Question

2. Amulatto Indian (AaBbCc) marries a very light skinned
American lady. What are the chances of their of having
a baby with fairly light skin?

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Answer 1

Answer:

Light Skin

Explanation:

Answer 2

Answer:

When a mulatto male individual marries a very light (american lady) female, the mulatto (AaBbCc) produces eight different types of gametes, whereas the american lady parent (aabbcc) produces only one gamete. thus generating 8 different genotypes. When mated, there will be one mulatto, three fair hers, three light hers, and only one albino offspring hers. Therefore, the proportion of albino offspring is only (1/8) x 100 = 12.5%.

The chances of their of having a baby with fairly light skin is 12.5%

So the correct answer is 12.5%.

              Human skin color is due to the presence of melanin pigment. The higher the pigment concentration, the darker the skin. Here, skin color changes are controlled by her 3 genes and 6 alleles. The dominant alleles A, B, and C encode dark skin tones, and the recessive alleles a, b, and c encode light skin tones. Black parents have a very dark skin phenotype and a genotype with the dominant allele AABBCC, while albino parents have a very light skin phenotype and a genotype with the recessive allele aabbcc.

• The F1 generation has a medium skin color phenotype and genotype AaBbCc.
• Crossing two of her F1 hybrids with eight gametes each yielded 64 offspring.
• In F2 offspring, 62 offspring exhibit only 30 genotypes, excluding two parental types. It indicates that different genotypes produce the same phenotype.

The phenotypic ratio is -

• 1 very dark:

• 6 Dark:
• 15 Pretty Dark:
• 20 Medium:
• 15 Very Easy:
• 6 lights:
• 1 Very easy.

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