Question

2. An auto velocity decrease from 20m/sec to 6m/sec while covering distance 70m. find the acceleration ???
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Answer 1

Step-by-step explanation:

S=70m

v^2-u^2=2as

36-400=2a*70

a=-2.6m/s^2

Answer 2

Answer:

Initial velocity =20m/s

Final velocity =6m/s

Distance covered=70m

a=Vsquare-Usquare/2s

a=36-400/2×70

a= -364/140 = - 2.6m/s square.

Negative acceleration is called retardation..