Question

2. An elastic ball at rest with coefficient of
restitution - is dropped from a height h on a
smooth floor. The total distance covered by the ball
is
1)5/3h
2)5h
3)3h
4)4/3h​

Answer 1

Answer:

Total distance covered by the ball before it comes to rest =[(1+e^2)/(1-e^2)]×h

.•. s= [{1+(1/2)^2}/{1-(1/2)^2}]h

=h(5/4)÷(3/4)

=(5/3)h

Answer 2

See the attachment

Good luck