Question

2.An electron is moving in a circular path having diameter of 28mm. So find the distance after 1.5 revolutions.[Take π=22/7]
​

Answer 1

Answer:

Given :

An electron is moving in a circular path.

Diameter of circular path = 28m

Radius of circular path = 28/2 =14m.

To find :

Distance covered by the electron after 1.5 revolutions.

Formula used :

$Circumference \: of \: circle = 2\pi r$

Solution :

Distance covered in 1 revolution = circumference of circle

$\\ Distance \: covered \: in \: 1 \: revolution = 2\pi r \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 2 \times \frac{22}{7} \times 14 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 88 \: m$

Therefore,

$Distance \: covered \: in \: 1.5 \: revolution = 1.5 \times 88 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 132 \: m$