Math, asked by varsha079, 1 year ago

plz anybody solve this

Attachments:

mkrishnan: answer is 4 i mean option 2

varsha079: yes... but how???

mkrishnan: delete one answer i send in detail

varsha079: okk

Anonymous: so cute

Anonymous: u r

Anonymous: like a 8 years babu

Anonymous: which class u study

varsha079: plz solve the question don't do time pass

Answers

Answered by Anonymous

I think 4 option is right

Answered by mkrishnan

Answer:

Step-by-step explanation:

n is positive integer

let k = 4n^2 + 8

[10^k + 1]^2 = [10^k]^2 + 2[10]^k + 1^2 here use [a+b]^2

= 10^2k + 2[10]^k +1

sum of digits in 10^2k is 1

sum of digits in 2[10]^k is 2

sum of digits in 1 is 1

sum of digits in 10^2k + 2[10]^k +1 is 1+2+1 = 4

mkrishnan: i hope u understand any doubt ask

varsha079: no... thanks

varsha079: plz solve other questions

mkrishnan: brilliant

varsha079: really you are great

varsha079: thank you so much

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