2. An electron is moving in a circular path of radius 5.1 x 10-'m
at a frequency of 6.8 x 1015 revolution/sec. The equivalent
current is approximately
(a) 5.1 x 10-'A
(b) 6.8 x 10-'A
(c) 1.1 x 10-A
(d) 2.2 x 10-A
Answers
Answered by
63
Answer:C
Explanation:
I=q/t
1/t = f
I=qf
For Electron q=1.6x10^-19
I= (1.6x10^-19)x(6.8x10^15)
I=1.1x10^-3
Regards..
Answered by
0
Answer:
Option C
Hope this helps you.
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