Question

2. An object moves from A to D along a rectangular path as
shown in the given figure. Find:
a. the distance covered by the object,
b. the displacement of the object. ​

Answer 1

Answer:

Distance = Length of path travelled

=AB+BC

=15+9

=24km

Displacement = Shortest path from initial to final position

=AC

=

(AB)

2

+(BC)

2

{Pythagoras Theorem}

=

225+81

=17.5km

solution

Expand-image

Answer 2

Answer:

Let the rectangle be ABCD,

a. The distance covered by the object = AB+BC+CD

(Distance is the total magnitude of length moved by the object from the initial to the final point)

b. The displacement of the object = DA

( Displacement is the shortest distance from the initial to the final point.)

Explanation:

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