Question

2. An ore contains 15% iron. How much ore will be required to get 18 kg of iron
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Answer 1

Answer:

100 kg of an ore contains 15 kg of iron.

Let mass required to obtain 18kg of an iron be = x

Then,15/100*x=18kg

x=1800kg/15=120k

So,the required amount would be

120...

Answer 2

Step-by-step explanation:

Mass required to obtain 18kg of iron is '120kg'. Answer: 100kg of an ore contains 15kg of iron. Then, 15/100 * x = 18kg ⇒ x = 1800kg / 15 = 120kg.