Math, asked by sandeepsharma35081, 7 months ago

-√2 and √2 are two of the zeroes of the p(x) - 2x4 + 7x3 - 8x2 - 14x + 8 find the remaining zeroes of p(x).

Answers

Answered by shashwatroy

0

Answer:

divide p(x) by x^2-2 and then find the roots of the resulting quadratic

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