Question

2 and 3 are zeros of the polynomial (x-2)(x-3) verify ​

Answer 1

Step-by-step explanation:

q(X)= x²+x-6=0

Replace the given values to verify the zeros.

q(2)=2²+2-6=0

=4+2-6=0

=6-6=0

=0=0

It can be the one zero.

And another one,

=3²+3-6=0

=9+3-6=0

=12-6=0

=6

so, it is not a zero.

Hope it will help you

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# jai hind #

Answer 2

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q(X)= x²+x-6=0

Replace the given values to verify the zeros.

q(2)=2²+2-6=0

=4+2-6=0

=6-6=0

=0=0

It can be the one zero.

And another one,

=3²+3-6=0

=9+3-6=0

=12-6=0

=6

so, it is not a zero.