Question

2 angles of a triangle are equal and the third angle is greater than each one of them by 18° find the angles
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Answer 1

Answer:

Step-by-step explanation:

There are 3 angles in a triangle.

In the given triangle two angles are equal.

Let us consider as the both angles are of x∘.

and the 3rd angle is 18° greater than both the equal angle.

so the 3rd angle = (x+18)°

We know that the sum of three angles of a triangle = 180°

so x° + x° + (x+18)° = 180°

=> (3x+18)° = 180°

=> (3x)° = (180-18)°

=> x° = (162/3)°

=> x° = 54°

So the equal angles both are 54°, and the 3rd angle is (54+18)° = 72°

The three angles of the triangles are 54°,54°,72°.

Hope it helps you.