Question

2} Bear a two digit number in mind .without disclosing it construct a puzzle, create two algebraic relations between the two digit of the number and solve the puzzle

Answer 1

Thank you for asking this question. Here is your answer:

We will answer this question by assuming the number to be x

This is how we are going to solve this:

3x + (50+40) =300

x = 300-90

=210

210/3

=70

70 is the final answer for this question.

If there is any confusion please leave a comment below.

Answer 2

Let us assume the two digit number to be 38.

Puzzle part:

We need to construct two algebraic expressions relating the digits of the number.

First relation : There is a two digit number, whose one digit is one less than thrice the other.

Let the two digit number be 10y+x.

y = 3x-1 or x = 3y -1 (Since its not mentioned which digit is greater)

Second relation : The sum of digits of the number is 11, with the unit digit greater than the tens.

So, y+x=11 and x > y

Now solving

y = 3x - 1

y + x =11

3x -1 + x =11

4x =12

x = 3

y = 3(3) -1 =8

We neglect this answer, as it does not follow the condition x > y.

Now solving,

x = 3y -1

y + x =11

y + 3y -1 =11

4y =12

y =3

x = 3(3)-1=8

∴ x= 8 ; y=3

Hence the two-digit number is 38.