2 bulbs of 100w and 60w connected with 220v calculate the crrent
Answers
Dear Friends, you did not mention it is series or parallel circuit im giving u the both
IN SERIES CIRCUIT
1. When bulb are connected in series "CURRENT" is same , While "VOLTAGE" will be "DIVIDED" Across Each Circuit According to the Position of the circuit connected (As in Increase order)
2. And Voltage Is directly proportional to Light. If voltage is high than it will glow brightly and if voltage is low it will dim.
3. Now Consider V = 220v,
R1 = 100w
R2 = 60w
So P = V^2/r therefor R1 = (220)^2/100 = 484ohm
R2 = (220)^2/60 =806.7ohm
So According to the OHM's Law V = IR
Resistance Directly proportional to Voltage.
so Voltage Directly proportional to Light.
Hence 40 watt bulb will glow more Brightly rather than 100w.
current in the circuit =V/total R =220/[484ohm+806.7ohm]
=220/1290.7 = 0.17 Amp ANS
IN PARALLEL CIRCUIT
Total supply voltage = 220v
Rated power of first bulb = 100 watt
So, current through it, I=p/v= 100/220= 0.45 amps
Resistance offered by first bulb =220/.45= 488 ohms
Rated power of second bulb =60 watts
Voltage is same, so current through is I=p/v= 60/220= 0.27 amps
Resistance of second bulb = 220/.27=814 ohms
So total current in the circuit is [ 0.27 amps+0.45 amps]
=0.72 amps ANS