Math, asked by ssatvik6717, 1 year ago

2 buses moving towards each other from town a to town b which are 480 km apart it took 1st bus from a to b is 8hours and bus back 10 hours find when and where 2 buses will meet

Answers

Answered by Anonymous
14
\textbf{\huge{ANSWER:}}

\sf{Given:}

Distance between towns, A and B = 480 km

Time taken by \tt{Bus_{1}} to cross the town = 8 hours

Time taken by \tt{Bus_{2}} to cross the town = 10 hours

Therefore, we can say that;

\tt{Speed\:of\:Bus_{1}} = \frac{480}{8}\\ km/hr

=》 60 km/hr

\tt{Speed\:of\:Bus_{2}} = \frac{480}{10}\\ km/hr

=》 48 km/hr

\tt{Relative\:Speed = 60 + 48 km/hr}

=》 108 km/hr

Time taken = \frac{Distance}{Speed}\\

=》 \frac{480}{108}\\

=》 \tt{Time = 4.44\:hours}

Distance = Speed × Time

=》 108 × 4.44

=》 \tt{Distance = 479.52\:km}
Answered by kshitij3996
0

Answer:

Both the busses will meet at time(t) = 4.44hrs. Distance each bus travels before meeting is 479.52 km.

Step-by-step explanation:

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