2 by 3 and 1 are the solutions of equation MX square + n X + 6 equal to zero find the value of M and n
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Answered by
57
Answer:
m=9 , n = -15
Explanation:
Given equation mx²+nx+6 =0
2/3 and 1 are the two
solutions.
i ) substitute x = 2/3 in the
equation,we get
m×(2/3)²+n(2/3) + 6 = 0
=> (4m/9)+2n/3 + 6 = 0
LCM of 9 and 3 is 9
=> (4m/9)+(6n/9)+(54/9)=0
=> (4m+6n+54)/9=0
=> 4m+6n+54 = 9×0
=> 4m+6n+54=0
Divide each term by 2 , we get
=> 2m+3n+27=0----(1)
ii) substitute x=1 , in the equation ,we get
=> m+n+6 = 0
=> m = -n-6 ----(2)
Substitute (2) , in (1) we get
=> 2(-n-6)+3n+27=0
=> -2n-12+3n+27=0
=> n+15=0
=> n = -15
Now ,
Put n = -15 in equation (2) , we get
m = -(-15)-6
= 15-6
= 9
Therefore,
m=9, n = -15
••••
m=9 , n = -15
Explanation:
Given equation mx²+nx+6 =0
2/3 and 1 are the two
solutions.
i ) substitute x = 2/3 in the
equation,we get
m×(2/3)²+n(2/3) + 6 = 0
=> (4m/9)+2n/3 + 6 = 0
LCM of 9 and 3 is 9
=> (4m/9)+(6n/9)+(54/9)=0
=> (4m+6n+54)/9=0
=> 4m+6n+54 = 9×0
=> 4m+6n+54=0
Divide each term by 2 , we get
=> 2m+3n+27=0----(1)
ii) substitute x=1 , in the equation ,we get
=> m+n+6 = 0
=> m = -n-6 ----(2)
Substitute (2) , in (1) we get
=> 2(-n-6)+3n+27=0
=> -2n-12+3n+27=0
=> n+15=0
=> n = -15
Now ,
Put n = -15 in equation (2) , we get
m = -(-15)-6
= 15-6
= 9
Therefore,
m=9, n = -15
••••
farook16:
Did you pls my question
pls
what is your doubt
How6n and 54are come
2n/3 = (2n×3)/(3×3) = 6n/9
6 = (6×9)/9 = 54/9 To make like terms we have to do like this
Thank u
do you understand .
Yes
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Answer:
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