Question

2. Calculate the acceleration of the moon towards earth's center. (AS)
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Answer 1

Answer:

The centripetal acceleration of the moon is v2/r. Details of the calculation: (a) The distance the moon travels in 27.3 days is d = 2πr = 2.41*109 m. Its speed is v = d/(27.3 days) = (d/(2.36*106 s)) = 1023 m/s.

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Answer 2

The acceleration due to gravity on the surface of the Moon is approximately $1.625m/s2$ about $16.6$$%$percentage that on Earth's surface or $0.166 ɡ.$

Explanation:

• The Earth's gravity keeps the Moon orbiting us. It keeps changing the direction of the Moon's velocity. This means gravity makes the Moon accelerate all the time, even though its speed remains constant.

• Calculating acceleration involves dividing velocity by time or in terms of SI units, dividing the meter per second $[m/s]$ by the second $[s].$Dividing distance by time twice is the same as dividing distance by the square of time. Thus the SI unit of acceleration is the meter per second squared .

• Gravitational Acceleration:$g = (G × Mass)/(distance from the center)2.$

• Comparing gravitational accelerations: acceleration at position$A = acceleration at position B × (distance B/distance A)2.$

• Calculating mass:$Mass = (g × distance2)/G.$

• The  $9.8 m/s²$  we feel is caused by the Earth accelerating upward like a rocket! . The relativistic point of view would be that the space around the Earth is compressing, but the atoms of the Earth resists this compression. This means that the surface of the Earth is constantly accelerating upwards.