2) Calculate the amount of Ca(OH)2 formed when 56 g of CaO reacts with 10 g
water.
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CaO+H
2
O→Ca(OH)
2
One mole of CaO will give one mole of calcium hydroxide.
The molar mass of calcium hydroxide is 40.1+2(16+1)=74.1g/mol.
370 grams of calcium hydroxide corresponds to
74.1g/mol
370g
=5.0 moles.
Hence, 5.0 moles of CaO are required to react with an excess of water to form 370 grams of calcium hydroxide.
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