Question

2) Calculate the force that must be exerted on the smaller piston of area of cross-section 25 cm ^ 2 so that a load of 1500N can be lifted on the larger piston of area of cross section 150 cm ^ 2 ?​

Answer 1

Answer:

20 N

Explanation:

we know that Pressure= Force / Area

=> Pressure=2/10 = 0.2 Nun-2

Now, Pressure=0.2

Again Force = Pressure x Area

Force = 0.2 x 100 = 20 N