Question

2.Calculate the workdone by a force acting on a body of mass 10kg changes its

velocity from 4m/s to 10 m/s.​

Answer 1

Answer:

420 Joules

Explanation:

Work done by a force = Δ K.E. So, just put the values and you will get your answer. Hope, this helps.

Answer 2

Given :

Mass of body = 10 kg

Initial velocity = 4 m/s

Final velocity = 10 m/s

To Find :

Work done by applied force.

Solution :

❒ As per work - kinetic energy kinetic, work done by applied force is always equal to the change in kinetic energy of moving object$.$

Mathematically, W = ∆K = K' - K

• W denotes work done
• K' denotes final kinetic energy
• K denoted initial kinetic energy

Kinetic energy of body of mass m moving at a velocity of v is given by

• K = 1/2 mv²

By substituting the given values;

➠ W = K' - K

➠ W = 1/2 mv² - 1/2 mu²

➠ W = 1/2 m (v² - u²)

➠ W = 1/2 × 10 × (10² - 4²)

➠ W = 5 (100 - 16)

➠ W = 5 × 84

➠ W = 420 J