2 capacitor of capacitance 3 mf and 6 mf are connected in series with a cell of 12 volt . find their equivalent capacitance and charge over 6 mf capactor?
Answers
Answer:
answer 200 v
Explanation:
PHYSICS
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Asked on December 26, 2019 by
Shaurya Dan
Two capacitors of 3μF and 6μF are connected in series and a potential difference of 900V is applied across the combination. They are then disconnected and reconnected in parallel. The potential difference across the combination is
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ANSWER
Let C1=3 μF,C2=6 μF
C1 and C2 are connected in series with potential difference V=900 V acros the combination
Thus for the series combination Charge on both capacitor is same
∴C
1
V
1
=C
2
V
2
=Q ...1
∴
V
2
V
1
=
C
1
C
2
=2 μC ...2
also V
1
+V
2
=900 V ...3
From 2 and 3
V
2
=300 V and V
1
=600 V
Therefore charge on each capacitor Q=300×6=600×3=1800 μC
When these capacitors are disconnected and reconnected in parallel the charge is distributed and the potential difference is same
∴
C
1
Q
1
=
C
2
Q
2
=V ...4
∴
Q
2
Q
1
=
C
2
C
1
=
2
1
...5
and Q
1
+Q
2
=Q=1800 μC ...6
From 5 and 6
Q
1
=600 μC and Q
2
=1200 μC
Therefore the potential difference across the combination is V=
3
600
=
6
1200
=200 V
Ans is 200 V