2 children are at opposite ends of an aluminum rod. One strikes then end of the rod with a stone. Find the ration of times taken by the sound wave in air and in aluminum to reach the second child.
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Answers
Answered by
3
speed of sound in air = 346m/s
speed of sound in aluminium rod = 6420m/s
let the length of the rod be x
we know,
time = distance/speed
time taken in air = x/346
time taken in aluminium rod = x/6420
ratio =(x/346)/(x/6420)
= x/346 * 6420/x [reciprocal]
x would get cancelled
= 6420/346
after cancelling
= 18.55
Answered by
4
speed of sound in air = 346m/s
speed of sound in aluminium rod = 6420m/s
let the length of the rod be x
we know,
time = distance/speed
time taken in air = x/346
time taken in aluminium rod = x/6420
ratio =(x/346)/(x/6420)
= x/346 * 6420/x [reciprocal]
x would get cancelled
= 6420/346
after cancelling
= 18.5
speed of sound in aluminium rod = 6420m/s
let the length of the rod be x
we know,
time = distance/speed
time taken in air = x/346
time taken in aluminium rod = x/6420
ratio =(x/346)/(x/6420)
= x/346 * 6420/x [reciprocal]
x would get cancelled
= 6420/346
after cancelling
= 18.5
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