Chemistry, asked by harshbhardwaj8112, 1 year ago

2- chlorobutane is treated with sodium in dry ether. The major product is monochlorinated in the presence of light.the final product is

Answers

Answered by gadakhsanket
17
Hii dear,

# Wurtz reaction-

Alkyl halides react with sodium metal in presence of ether to form higher alkanes.

For example-

2R-X + 2Na ---> R-R + 2NaX

# When 2-chlorobutane is treated with sodium/dry ether, we get 3,4-dimethyl hexane

2 CH3-CH(Cl)-CH2-CH3 ---> CH3-CH2-CH(CH3)-CH(CH3)-CH2-CH3

# When monochlorinated in presence of light, 3,4-dimethyl hexane forms following possible products-

1)1-chloro-3,4-dimethylhexane

CH2(Cl)-CH2-CH(CH3)-CH(CH3)-CH2-CH3

2)2-chloro-3,4-dimethylhexane

CH3-CH(Cl)-CH(CH3)-CH(CH3)-CH2-CH3

3)3-chloro-3,4-dimethylhexane

CH3-CH2-C(CH3)(Cl)-CH(CH3)-CH2-CH3

Hope that helps...
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