2 complementary angles differ by 16°.Find the angles.
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Answered by
2
let the first angle be x
let the second angle x-16
x + x-16 = 90
x+x = 90+16
2x = 106
x = 106/2
x = 53
x-16 = 53 -16= 37
so the angles are 53 nd 37
check = 53+37 = 90
let the second angle x-16
x + x-16 = 90
x+x = 90+16
2x = 106
x = 106/2
x = 53
x-16 = 53 -16= 37
so the angles are 53 nd 37
check = 53+37 = 90
Rk9376:
Let one no
??
Let one angle be x then other no is 90- x
bit then how will u show difference of 16
but*
Answered by
1
x+×+16=90
2x=90-16
2x=90-16
2x=74
x=74/2
x=37
other angle=x+16=53
2x=90-16
2x=90-16
2x=74
x=74/2
x=37
other angle=x+16=53
Let on
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