2 consecutive natural no. are roots for a quadratic equation then find the equation
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Let k & k+1 be the roots
The required equation is given by :
x² - (Sum of the zeroes) x +( Product of the Zeros) =0
⟹ x² - ( k+k+1 ) x + ( k × ( k+1) ) = 0
⟹ x² - (2k+1)x + (k^2 +k) = 0
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