Math, asked by Vijay6776, 8 months ago

2 consecutive natural no. are roots for a quadratic equation then find the equation

Answers

Answered by pulakmath007
0

ANSWER ::

Let k & k+1 be the roots

The required equation is given by :

x² - (Sum of the zeroes) x +( Product of the Zeros) =0

⟹ x² - ( k+k+1 ) x + ( k × ( k+1) ) = 0

⟹ x² - (2k+1)x + (k^2 +k) = 0

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