Question

2.Construct a parallelogram ABCD in which
the diagonals AC=6cm, BD=4.8cm,and
the side AB =4cm​

Answer 1

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Steps :  

1.Draw ∠PAB = 45°.

2.Cut AD = 4.8 cm.

3.From D, draw an arc of radius 6 cm.

4.From B, draw an arc of radius 4.8 cm which meets first arc at C.

5.Join BC, CD, AD.

6.Thus ABCD is the required ||gm.

7.Draw perpendicular bisector XY of AD which cuts AD at P.

8.Join AC and BD which intersect at O.

9.Join OP and measure it.

10.OP = 3 cm.