Question

2. Construct APOR such that ZP = 70°, LR= 50°
OR=7.3 cm and construct its circumcircle.​

Answer 1

Answer:

In ∆PQR, m∠P + m∠Q + m∠R = 180° … [Sum of the measures of the angles of a triangle is 180°]  ∴ 70° + m∠Q + 50° = 180°  ∴ m∠Q = 180° – 70° + m∠Q + 50° = 180°  ∴ m∠Q = 180° – 70° – 50°  ∴ m∠Q = 60°Read more on Sarthaks.com - https://www.sarthaks.com/850566/construct-pqr-such-that-p-70-r-50-qr-7-3-cm-and-construct-its-circumcircle

Explanation:

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