Question

2(cos^2 45°+tan^2 60°) - 6(sin^2 45°-tan^2 30°) =6

Answer 1

Step-by-step explanation:

Trigo,........ =___=

2(cos^2 45°+tan^2 60°) - 6(sin^2 45°-tan^2 30°) =6

L.H.S

2(cos^2 45°+tan^2 60°) - 6(sin^2 45°-tan^2 30°)

2(1/2 +3 ) - 6(1/2-1/3)

2(7/2) - 6( 1/6)

14/2 - 6/6

7 - 1

= 6 = R.H.S

Hope it helps you!

Answer 2

Answer: I dont no sorry

Step-by-step explanation: