2(cos 45+tan²60)-6(sin³45"-tan³60") by
tan 30+ cot 60°
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1
Answer:
2 (cos
2
45
∘
+tan
2
60
∘
) - 6 (sin
2
45
∘
−tan
2
30
∘
)
=2[(
2
1
)
2
+(
3
)
2
]−6[(
2
1
)
2
−(
3
1
)
2
]
=2(
2
1
+3)−6(
2
1
−
3
1
)=2(
2
1+6
)−6(
6
3−2
) = 7−1=6
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