Math, asked by thestylishgirl39, 8 months ago

√2 cos 45° - tan^2 60°
evaluate without using trigonometric tables​

Answers

Answered by raushan6198
1

Answer:

 \sqrt{2}  \cos(45)  -  { \tan }^{2} 60 \\  =  \sqrt{2}  \times  \frac{1}{ \sqrt{2} }  -  { (\sqrt{3} )}^{2}  \\  = 1 - 3 \\  =  - 2 \:  \: ans.

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