Question

2 cos 67/sin 23 - tan 40/cot 50 - sin 90

Answer 1

The given expression

= 2(cos 67o/sin 23o) - (tan 40o/cot 50o) - sin90o

= 2(cos (90o - 23o)/sin 23o) - tan (90o - 50o)/cot 50o - sin90o

= 2(sin 23o/sin 23o) - cot 50o/cot 50o - sin90o

= 2 - 1- 1 = 0

Answer 2

The value of the expression is 0.

Step-by-step explanation:

Consider the provided information.

$\begin{array}{l}=\dfrac{2\cos67^o}{\sin23^o}-\dfrac{\tan{\displaystyle{\displaystyle40}^{{}^o}}}{\cot50^o}-\sin90^o\\\\=\dfrac{2\sin(90-67)}{\sin{\displaystyle23}}-\dfrac{\cot(90-40)}{\cot50}-1\\\\=\dfrac{2\sin23}{\sin{\displaystyle23}}-\dfrac{\cot50}{\cot50}-1\end{array}$

$\\=2-1-1\\\\=2-2\\\\=0$

Hence, the value of the expression is 0.

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