2 cos theta + 2√2 =3 sec theta
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2cosθ+2
2
=3secθ
2cos
2
θ+2
2
cosθ=
2
3
Let cos
2
θ=y
cosθ=
2
−1+2
y
2
+
2
y=
2
3
=0
⇒
2
−1+2
,
2
−1−2
y=
2
−
2
±
2−4(
4
3
)
cosθ=
2
1
,
2
−3
=
2
−
2
±
2+6
=
2
−
2
±2
2
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