Question

2 cos67°/sin23°-tan40°/cot50°-sin90°

Answer 1

$\large \boxed{{\boxed{ \underline{ \underline \blue{ \sf{ǫᴜᴇsᴛɪᴏɴ : }}}}}}$

$\pink{ \sf{ \frac{2 \: cos \: 67 \degree}{sin \: 23 \degree} - \frac{tan \: 40 \degree}{cot \: 50 \degree} - sin \: 90 \degree }}$

$\large \boxed{{\boxed{ \underline{ \underline \blue{ \sf{ᴀɴsᴡᴇʀ : }}}}}}$

$\blue{ \sf{ \frac{2cos \: 67 \degree}{cos(90 \degree - 23 \degree)} - \frac{tan40 \degree}{tan(90 \degree - 50 \degree)} - sin90 \degree }} \\ \\ \blue{ \sf{ =\frac{2cos \: 67 \degree}{cos \: 67 \degree } - \frac{tan40 \degree}{tan \: 40\degree} - sin90 \degree }} \\ \\ \blue{ \sf{ =\frac{2 \cancel{cos \: 67 \degree}}{ \cancel{cos \: 67 \degree }} - \frac{ \cancel{tan40 \degree}}{ \cancel{tan \: 40\degree}} - sin90 \degree }} \\ \\ \blue{ \sf{ = 2 - 1 - 1}} \\ \\ \blue{ \sf{ = 2 - 2}} \\ \\ \blue{ \sf{ = 0}}$

Answer 2

$\large \boxed{{\boxed{ \underline{ \underline { \sf{Question:-}}}}}}$

${ \bf{ \frac{2 \: cos \: 67 \degree}{sin \: 23 \degree} - \frac{tan \: 40 \degree}{cot \: 50 \degree} - sin \: 90 \degree }}$

$\large \boxed{{\boxed{ \underline { \sf{Answer:-}}}}}$

${ \bf{ \frac{2cos \: 67 \degree}{cos(90 \degree - 23 \degree)} - \frac{tan40 \degree}{tan(90 \degree - 50 \degree)} - sin90 \degree }} \\ \\ { \bf{ =\frac{2cos \: 67 \degree}{cos \: 67 \degree } - \frac{tan40 \degree}{tan \: 40\degree} - sin90 \degree }} \\ \\ { \bf{ =\frac{2 \cancel{cos \: 67 \degree}}{ \cancel{cos \: 67 \degree }} - \frac{ \cancel{tan40 \degree}}{ \cancel{tan \: 40\degree}} - sin90 \degree }} \\ \\ { \bf{ = 2 - 1 - 1}} \\ \\ { \bf{ = 2 - 2}} \\ \\ { \bf{ = 0}}$