Math, asked by arnabmalik, 10 months ago

2(cosa +sinb) (cos a— sinb)
=cos2a +cos2b​

Answers

Answered by thakursandhya713
1

Step-by-step explanation:

l.h.s

2(cosa+sinb)(cosa_sinb)

2(cos2a-sin2b)

2(cosa2a-(1-cos2b)

2(cos2a-1-cos2b)

2-1(cos2a+cos2b)

cos2a+cos2b

l.hs=r.h.s

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