2 cosec²30°+x.sin²60°-tan²30°=10 determine the value of x
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2cosec^2 30^{\circ}+x sin^2 60^{\circ} - \frac{3}{4} tan^2 30^{\circ}=10
2 (2)^2 + x ( \frac{\sqrt{3}}{2})^2 - \frac{3}{4}\times (\frac{1}{\sqrt{3}})^2 = 10
8 + \frac{3x}{4}-\frac{3}{12}=10
\frac{3x}{4}=10+\frac{1}{4}-8
\frac{3x}{4}=\frac{40+1-32}{4}
\frac{3x}{4}=\frac{9}{4}
\implies x = \frac{36}{12}= 3
Thus, the value of x is 3.
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