Question

The length of the rectangle is 10 m more than its breadth. If the perimeter of rectangle is 80 m, find the dimensions of the rectangle.​

Answer 1

Step-by-step explanation:

Length = x + 10 m

Breadth = x m

Perimeter = 80 m

Perimeter of rectangle = 2 (l + b)

80 = 2 (x + 10 + x)

= 40 = 2x + 10

= 30 = 2x

= x = 15

Length = x + 10 = 15 + 10 = 25 m

Breadth = x = 15 m

Answer 2

Let the breadth of rectangle be x m.

The length of rectangle is 10 m more than it's breadth.

So,

Length of rectangle = (x + 10) m

Also, given that perimeter of rectangle = 80 m

$\underline{ \boxed{ \rm{ \bold{Perimeter \:of\:rectangle \:=\:2(l\:+\:b)}}}}$

• l = length = (x + 10) m
• b = breadth = (x) m

Substitute the known values above

=> 80 = 2(x + 10 + x)

=> 80 = 2(2x + 10)

=> 80 = 4x + 20

=> 80 - 20 = 4x

=> 60 = 4x

=> 15 = x

=> x = 15

$\therefore$ Breadth of rectangle = x

=> 15 m

$\therefore$ Length of rectangle = x + 10

=> 15 + 10

=> 25 m

•°• Dimensions of the rectangle are 15 m and 25 m.