2 cross road,each of wide 10m,cut the right angles through the centre of a rectangular park of length 700m and breadth 300 m and parallel to it's sides. find the area of the roads. Also find the area of the park excluding cross road. Give the answer in hector.
Answers
Answer:
210,000
Step-by-step explanation:
because here is multiple
Two cross roads, each of width 10m, cut at right angles through the centre of a rectangular park of length 700m and breadth 300 m and parallel to it's sides. Find the area of the roads. Also find the area of the park excluding cross road. Give the answer in hectares.
Area of rectangular park = l × b
= (700) (300)
= 210000 m²
Length of the first cross road parallel to the length = 700 m
Breadth of the first cross road parallel to the length = 10 m
Area of the first cross road = (700) (10)
= 7000 m²
Length of the first cross road parallel to the length = 300 m
Breadth of the first cross road parallel to the length = 10 m
Area of the first cross road = (300) (10)
= 3000 m²
Area of the common part of the 2 cross roads with width 5 m that lies at the center of the rectangular park = (10) (10)
= 100 m²
Area of the 2 cross roads = Area of the 1st cross road + Area of the 2nd cross road - Common area
⇒ (7000 + 3000) - 100
⇒ 10000 - 100
= 9900 m²
9900 m² → 0.99 hectares
Area of park without cross roads = Area of rectangular park - (Sum of areas of the cross roads) + common area
= 210000 - (7000 + 3000) + 100
= 210100 - 10000
= 200100 m²
200100 m² → 20.01 hectares
★ Note -
1 hectare = 10000 m²
Hope this helps uh! ♡