Question

2 cube each of volume 64 CM cube are joined end to end find the surface area resulting cuboid

Answer 1

Given Volume of both cubes = 64cm^3

find one side = (64)^1/3 = 4

The cubes are joined end to end

Length = 8cm  

width = 4cm

height= 4 cm

Surface area,

2(lb+bh+hl)

2(32+16+32)

160 cm^2

Answer 2

Answer:

The Total Surface Area of the Cuboid is 160 c$m^{2}$

Step-by-step explanation:

Given:

Volume of the cubes = 64 c$m^{3}$

To find one side of the cube:

$\sqrt[3]{64}$

= 4 cm

Length of the new cuboid which is formed by joining both the cubes end to end = 4 + 4 = 8 cm

Breadth of the new cuboid which is formed by joining both the cubes end to end =  4 cm

Height of the new cuboid which is formed by joining both the cubes end to end =  4 cm

Formula to find the Total Surface Area of the cuboid :

${\boxed{\boxed{\sf{2(lb + lh + bh)}}}}$

TSA of the cuboid = 2 { (8)(4) + (8)(4) + (4)(4) }

=> 2 ( 32 + 32 + 16 )

=> 2 (80)

=> 160 c$m^{2}$

Therefore, the Total Surface Area of the Cuboid is 160 c$m^{2}$