Question

2 cube root 250 + 8 cube root 16 - 3 cube root 54 + 4th root 32

Answer 1

$2 \sqrt[3]{250} + 8 \sqrt[3]{16} - 3 \sqrt[3]{54} + \sqrt[4]{32} \\ \\ \tt = > 2 \sqrt[3]{2 \times {5}^{3} } + 8 \sqrt[3]{2 \times {2}^{3} } - 3 \sqrt[3]{2 \times {3}^{3} } + \sqrt[4]{ 2 \times {2}^{4} } \\ \tt = > 10 \sqrt[3]{2} + 16 \sqrt[3]{2} - 9 \sqrt[3]{2} + 2 \sqrt[4]{2} \\ \tt= > \sqrt[3]{2} (10 + 16 - 9) + 2 \sqrt[4]{2} \\ \tt = > \sqrt[3]{2} (26 - 9) + 2 \sqrt[4]{2} \\ \tt = > \red{17 \sqrt[3]{2} + 2 \sqrt[4]{2} }$