2 cubes each of volume 64 cm² are joined end to end.find the surface area of the resulting cuboid
Answers
volume of one cube=64^3
let 'a' be the side of the cube.
i;e. a^3=64
a=4 cm (4^3=64)
since both the cubes are joined it will become a cuboid with length 8 cm(4+4=8), breadth =4 cm and height =4 cm.
now surface area of the cuboid=2(l*b+b*h+h*l)
=2(8*4+4*4+8*4)
=2(32+16+32)
=2*80
=160 cm^2
Answer: 160cm².
Step by step explanation:
Given,
Volume of both cubes = 64cm³
Volume of one cube =a³
⇒ 64 = a³
⇒ (4) = a³
⇒ a=4
We know that, when two cubes are joined they form cuboid:
Length of cuboid=4+4= 8cm
Breadth of cuboid= 4cm
Height of cuboid= 4cm
Surface area of cuboid = 2(lb+bh+lh)
2(8×4+4×4+4×8)
= 2(32+16+32)
= 2(80)
= 160cm²
Therefore, Surface area of Cuboid is 160 cm².