Question

2 cubes each of volume 64 cm³ are joined end to end. Find the surface area of the resulting cuboid.

Answer 1

Answer:

160 $cm^2$

Step-by-step explanation:

Volume of cube = $a^3$

${a}^{3} = 64 \\ \\ a = \sqrt[3]{64} \\ \\ a = 4 \: cm$

When we attach two cubes , the length of resulting cuboid is 2 times the length of cube . Breadth and Height of cuboid is same as edge of cube.

Length of cuboid (l) = 8 cm

Breadth of Cuboid (b) = 4 cm

Height of Cuboid (h) = 4 cm

Surface Area of Cuboid = 2(lb+lh+bh)

Surface Area of Cuboid = 2(32+32+16)

Surface Area of Cuboid = 2*80 $cm^2$

Surface Area of Cuboid = 160 $cm^2$

Hope it helps u

Have a great day ahead

Annyeong

Answer 2

Step-by-step explanation:

a^3 = 64

a^3 =64

a^3= 64

a =

tsa

2 lb lb bh