2 cubes each of volume 64 cm3
are joined end to end. Find the surface area of the
resulting cuboid.
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Answer
Given, volume of each cube is 64 cm³
⇒s³=64
⇒s=∛64
⇒s=4 cm.
When two cubes are joined ,
the length of the resulting cuboid(l) = side + side = 4+4 = 8 cm
its breadth(b) = side = 4cm
And its height(h) = side = 4cm
Total surface area of a cuboid = 2(lb+bh+hl)
⇒TSA=2[(8)(4)+(4)(4)+(4)(8)]
⇒TSA=2(32+16+32)
⇒TSA = 2(80)
⇒TSA = 160 cm²
∴ The surface area of the resulting cuboid is 160 cm².
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