2 cubes each of volume 64 cmcube are joined end to end. Find the surface area of the
Yesulting cuboid.
Answers
Answer:
Surface area of cuboid is 640 cm².
Step-by-step explanation:
Volume of cube = 64 cm³
i.e. (side) ³ = 64 cm³
=> side = 4 cm
Length of cube = 4 cm
2 cube are joined together,
Length of cuboid,L = 4 + 4 = 8 cm
Breadth of cuboid,B = 4 cm
Height of cuboid,H = 4 cm
Surface area of cuboid
= 2*L*B + 2*L*H + 2*B*H
=2*(L*B + L*H + B*H)
=2*[(8*4) + (8*4) + (4*4)]
=2*[32 + 32 + 256]
=2*[320]
= 640 cm²
Answer: 160cm².
Step by step explanation:
Given,
Volume of both cubes = 64cm³
Volume of one cube =a³
⇒ 64 = a³
⇒ (4) = a³
⇒ a=4
We know that, when two cubes are joined they form cuboid:
Length of cuboid=4+4= 8cm
Breadth of cuboid= 4cm
Height of cuboid= 4cm
Surface area of cuboid = 2(lb+bh+lh)
2(8×4+4×4+4×8)
= 2(32+16+32)
= 2(80)
= 160cm²
Therefore, Surface area of Cuboid is 160 cm².