Math, asked by pravin4788, 1 year ago

2 diagobals of a rectangle are of length (4x+1) cm and (2x+15) cm then the value of x is

Answers

Answered by akshitchadha0
4

Answer:

x=7

Step-by-step explanation:

4x+1 = 2x+15

4x-2x = 15-1

2x = 14

x =14/2

x=7

Answered by pulakmath007
1

The value of x = 7

Given :

2 diagonals of a rectangle are of length (4x + 1) cm and (2x + 15) cm

To find :

The value of x

Solution :

Step 1 of 2 :

Form the equation

Here it is given that 2 diagonals of a rectangle are of length (4x + 1) cm and (2x + 15) cm

Since length of two diagonals of a rectangle are equal in measure

So by the given condition

4x + 1 = 2x + 15

Step 2 of 2 :

Find the value of x

\displaystyle \sf{ 4x + 1 = 2x + 15 }

\displaystyle \sf{ \implies 4x  -  2x  =  15 - 1}

\displaystyle \sf{ \implies  2x  =  14}

\displaystyle \sf{ \implies  x  =   \frac{14}{2} }

\displaystyle \sf{ \implies  x  =  7}

Hence the required value of x = 7

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