Question

Maths
Chapter triangles

Answer 1

It is Given AB=DB
AC=DC
Third side BC is common to both of them .
Therefore ∆ACB=~∆DCB

Using Corresponding Parts of congruent triangles (CPCT)we get,
/_ABC=/_DBC

Therefore
2x-4=58°
2x. = 58-4
2x. = 54
x. =54÷ 2
x. = 27


Again By CPCT we get
/_ACB=/_DCB

Therfore
y+15°=63°
y. =63-15
y. =48°


Therefore ,x=27° and y=48°

Answer 2

Answer is in the attachment