Question

2 dice are rolled then probability of getting a total of 9 is

Answer 1

S.S =( 1,1) ,(1,2), (1,3),(1,4),(1,5),(1,6),
(2,1)(2,2)(2,3),(2,4),(2,5),(2,6),
(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),
(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),
(5,1),(5,2),(5,3),(5,4),(5,5,),(5,6),
(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)

n(S) =36

Event getting a total of 9
Event A : (6,3),(3,6),(4,5),(5,4)
n(A) : 4
P(A) : n(A) / n(S)
4/36 =2/18 =1/9
the total getting 9 is 1/9

Answer 2

1/9 is the probablity.