Question

2.Draw the graphs of the equations 3x-2y+6=0 and x+2y-6=0 in the same graph paper.Find the area of triangle formed by the two lines and x axis 4 points

Answer 1

Answer:

Equation of the first line is 3x + 2y - 6 = 0

Slope-intercept form of the equation is,

2y = -3x + 6

---------(1)

Table for input-output values will be,

x   0     2    4  

y   3     0   -3

Similarly, second equation is,

x + 2y - 6 = 0

2y = -x + 3

y =  --------(2)

Table for input-output values will be,

x      0      2      6

y      3      2      0

Now by plotting these points we get a triangle with vertices (0, 3), (2, 0) and (6, 0)

Area of the given triangle =  

Base = 4 units

Height = 3 units                                        

Area =  = 6 square units

Step-by-step explanation:

pls mark brainiest