Question

2. Each of the two equal angles of a triangle is twice the third angle. Find the angles of the
triangle.​

Answer 1

Answer:

let third angle be = x

now two equal angles be = 2x

sum of angles of a triangle=180°

x+2x+2x=180°

5x=180°

x=36°

Answer 2

Let the third angle be = x

if the two angle is twice of the third angle then

first angle = 2x

second angle =2x

sum of the angle of the triangle = 180 so,

x + 2x + 2x = 180

5x = 180

x = 180/5 = 36

so third angle = 36

first angle = 2x = 2*36 = 72

second angle = 2x = 2*36 = 72.