Question

2 equal masses each m are hung from a balance whose scale pans differ in vertical height by h then error in weighing in terms of density of earth rho??

Answer 1

Given :

Mass of particles = m

To find :

Error in weighing in terms of density

Solution :

• w₁ = mg

• w₂ = m(1 - (2h/R) )g

       Δw = (2h/R)mg

• We know that   g=GM/R₂

        g=G(4/3)ρπr₃ / R₂

        g = (4/3)gRρ

• By substituting the value

      Δw = (2h/R)m×(4/3)gRπρ

      Δw = (8/3)πgmhρ

The error in weights is  (8/3)πgmhρ