2 equal sides of a triangle are each 5 meters less than twice the third side . perimeter of the triangle is 55 meters, find the length of its sides?
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Let the Length of third side is ( x ) m
Each sides from 2 side = ( 2x - 5 ) m
Given, perimeter = 55 m
=> x + 2x - 5 + 2x - 5 = 55
=> 5x - 10 = 55
=> x = 65/5
=> x = 13 m
Hence, Length of sides are :
x = 13 m
( 2x - 5 ) = 2(13)-5 = 21 m
( 2x - 5 ) = 21 m
Each sides from 2 side = ( 2x - 5 ) m
Given, perimeter = 55 m
=> x + 2x - 5 + 2x - 5 = 55
=> 5x - 10 = 55
=> x = 65/5
=> x = 13 m
Hence, Length of sides are :
x = 13 m
( 2x - 5 ) = 2(13)-5 = 21 m
( 2x - 5 ) = 21 m
Answered by
0
Heya !!
Let third side of a triangle be X m.
Two equal sides = ( 2X - 5 ) m.
Perimeter of triangle = 55
2 ( Equal sides ) + Third side = 55
2 ( 2X - 5 ) + X = 55
4X - 10 + X = 55
5X = 55 + 10
X = 65/5
X = 13 m
Third side = X = 13 m
And,
2 Equal sides = 2X - 5 = 2 × 13 - 5 = 21 m.
Let third side of a triangle be X m.
Two equal sides = ( 2X - 5 ) m.
Perimeter of triangle = 55
2 ( Equal sides ) + Third side = 55
2 ( 2X - 5 ) + X = 55
4X - 10 + X = 55
5X = 55 + 10
X = 65/5
X = 13 m
Third side = X = 13 m
And,
2 Equal sides = 2X - 5 = 2 × 13 - 5 = 21 m.
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