Question

2. Express each of the following temperatures in °F.
a. 55°C
b. 100°C
c. 0°C
d. 20°C​

Answer 1

Answer:

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Explanation:

Formula

F = 9C+160/5

F = 9×55+160/5 = 655/5 = 131°F

F = 9×100+160/5 = 1060/5 = 212°F

F = 9×0+160/5 = 160/5 = 32°F

F = 9×20+160/5 = 340/5 = 68°F

Answer 2

Explanation:

°C = ($\frac{9}{5}$×°F+32)°F

1. 55°C = ($\frac{9}{5}$×55+32)°F = 131°F
2. 100°C = ($\frac{9}{5}$×100+32)°F = 212°F
3. 0°C = ($\frac{9}{5}$×0+32)°F = 32°F
4. 20°C = ($\frac{9}{5}$×20+32)°F = 68°F